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Topic # 236001 13-May-2018 14:17
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n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2

 

Can someone explain the steps taken in between?

 

Thanks!


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  Reply # 2015134 13-May-2018 14:31
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n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2

 

Assuming all of it is over 2 not just the "2(n+1) over 2"

 

(n+1) is common factor. so n(n+1) + 2(n+1) becomes

 

(n+1) (n+2)

 

Then just chuck it all over 2 to get

 

(n+1) (n+2) over 2


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  Reply # 2015137 13-May-2018 14:41
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As above reply, what you have is

 

xy + xz = x(y+z)

 

 

if it makes looking at it any simpler.

 

 

(with a factor of half out the front)



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  Reply # 2015141 13-May-2018 14:45
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Ahh, thank you both, that makes sense now.


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