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JoeMNZ

2 posts

Wannabe Geek


#73381 13-Dec-2010 12:23
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Alright! Hey guys, First time I've actually needed to post something on any of these forums..

I'm having some problems with this admin panel I'm building in PHP, I can't seem to insert into the table I need to!

Heres a small part of the code which receives stuff posted to it from a form..


            $nav = $row['nav'];
            $editable = $row['editable'];
            $withlinks = $row['withlinks'];
            $name = $_POST['name'];
            $title = $_POST['title'];
            $content = $_POST['content'];
           
            mysql_query("INSERT INTO links (name, title, content, nav, editable, withlinks) VALUES ('$name', '$title', '$content', '$nav', '$editable', '$withlinks')");
            /** mysql_query("INSERT INTO links (name, title, content, nav, editable, withlinks) VALUES ('$name', '$title', '$content', '$nav', '$editable', '$withlinks')"); **/


The reason I have the same query twice with one commented out is because, last time I had an error with querys, I copied the same type of query off a tutorial site, and changed the variables to suit, and it worked! It was exactly the same "visually" as what I had typed..

I use Notepad++

Umm that's about all,
Thanks in advance!
Joe

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itxtme
2102 posts

Uber Geek
+1 received by user: 557


  #416480 13-Dec-2010 12:44
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Whats $row ?? its very hard to comment without seeing all of the php statement. You have received half the variables via _POST and the other half just have $row



Kraven
738 posts

Ultimate Geek
+1 received by user: 190


  #416482 13-Dec-2010 12:47
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Put:

echo mysql_error();

on the next line after your query and that give what error (if any) mysql is returning.

JoeMNZ

2 posts

Wannabe Geek


  #416484 13-Dec-2010 12:50
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OK! Problem resolved........

I was simply thinking I was so good that I could ignore the fact that I'm trying to insert it into the wrong table...

Sorry for wasting your time!



rvangelder
352 posts

Ultimate Geek


  #416501 13-Dec-2010 13:21
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