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Topic # 236001 13-May-2018 14:17
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n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2


Can someone explain the steps taken in between?



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  Reply # 2015134 13-May-2018 14:31
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n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2


Assuming all of it is over 2 not just the "2(n+1) over 2"


(n+1) is common factor. so n(n+1) + 2(n+1) becomes


(n+1) (n+2)


Then just chuck it all over 2 to get


(n+1) (n+2) over 2

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  Reply # 2015137 13-May-2018 14:41
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As above reply, what you have is


xy + xz = x(y+z)



if it makes looking at it any simpler.



(with a factor of half out the front)

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  Reply # 2015141 13-May-2018 14:45
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Ahh, thank you both, that makes sense now.

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