n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2
Can someone explain the steps taken in between?
Thanks!
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n(n+1) + 2(n+1) over 2 = (n+1) (n+2) over 2
Assuming all of it is over 2 not just the "2(n+1) over 2"
(n+1) is common factor. so n(n+1) + 2(n+1) becomes
(n+1) (n+2)
Then just chuck it all over 2 to get
(n+1) (n+2) over 2
xy + xz = x(y+z)
if it makes looking at it any simpler.
(with a factor of half out the front)
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